[LeetCode] Container With Most Water

Given n non-negative integers a1, a2, ..., an , where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of the line i is at (i, ai) and (i, 0). Find two lines, which, together with the x-axis forms a container, such that the container contains the most water.

Notice that you may not slant the container.

 

Example 1:

Input: height = [1,8,6,2,5,4,8,3,7] Output: 49 Explanation: The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49.

Example 2:

Input: height = [1,1] Output: 1

Example 3:

Input: height = [4,3,2,1,4] Output: 16

Example 4:

Input: height = [1,2,1] Output: 2

 

Constraints:

• n == height.length
• 2 <= n <= 105
• 0 <= height[i] <= 104

class Solution {
public:
    int maxArea(vector<int>& height) {
        int maxVal = 0;
        int left = 0;
        int right = height.size() - 1;
        while (left <= right)
        {
            maxVal = max(maxVal, min(height[left], height[right]) * (right - left));
            if (height[left] < height[right]) left++;
            else right--;
        }
        return maxVal;
    }
};